Errors in “Does 1 = 2?” Proofs


1st Proof

x = 1 set x equal to 1
x2 = x multiply both sides by x
x2 - 1 = x - 1 subtract 1 from both sides
(x - 1)(x + 1) = x - 1 separate left side into factors
x + 1 = 1 divide both sides by (x - 1)
1 + 1 = 1 substitute 1 for x
2 = 1

Division by (x-1) is not allowed since x=1 and therefor x-1=0 and division by zero is an undefined operation.



2nd Proof

(-1)(-1) = 1
the square of -1 is 1
-1 = 1/-1
divide both sides by -1
-1/1 = 1/-1
identity operation; for all real (or complex) x, x = x/1
i/1 = 1/i
take the square root of both sides (i=sqrt(-1))
i/2 = 1/2i
divide both sides by two
i2/2 = i/2i
multiply both sides by i
-1/2 = 1/2
substitute -1 for i2 and 1 for i/i
-1/2 + 3/2 = 1/2 + 3/2
add 1 1/2 (3/2) to both sides
1 = 2

There are two square roots for -1, i and -i and for 1, 1 and -1.



3rd Proof

x2 = x+x+x+...+x (x times) definition of x2; x not equal to zero
2x = 1+1+1+...+1 (x times) take derivative of both sides; 
derivative of xn = nxn-1
2x = x  x = 1+1+1+...+1 (x times)
2 = 1 divide both sides by x (x not equal to zero)

Only continuous functions have derivatives.  x2 as defined above is valid only for non-negative whole numbers and is therefor not a continuous function.









This page was last updated on November 3, 2009.
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